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The minutes hand of a clock length is 10.5 cm. Then area swept by it in 10 minutes is ……… cm2.(A) 115.5 (B) 57.75 (C) 11.55 (D) 575.5 |
Answer» Correct option is: (B) 57.75 The length of the minute hand of a clock is r = 10.5cm. \(\because\) Area swept by minute hand in 1 hour (60 minutes). = \(\pi r^2 \, cm^2\) \(\therefore\) Area swept by minute hand in 10 minutes = \(\frac {\pi r^2}{60} \times 10 cm^2\) = \(\frac {\pi r^2}{6} = \frac 16 \times \frac {22}7 \) x 10.5 x 10.5 = 11 x 0.5 x 10.5. = \(57.75 \, cm^2\). Correct option is: (B) 57.75 |
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