The missing tenn in the following equation is: `2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+...`A. `Sn^(4+)`B. `Sn^(3+)`C. `Sn^(2+)`D. `Sn^(+)`

The missing tenn in the following equation is: `2Fe^(3+)+Sn^(2+) to 2F

1.	The missing tenn in the following equation is: `2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+...`A. `Sn^(4+)`B. `Sn^(3+)`C. `Sn^(2+)`D. `Sn^(+)`
Answer» Correct Answer - C

Discussion

No Comment Found

Related InterviewSolutions

In the following reaction `3Br_(2)+6CO_(3)^(2-)+3H_(2)O=5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)`A. bromine is oxidised carbonate is reduced,B. bromine is reduced, carbonate is oxidisedC. bromine in neither reduced nor oxidisedD. bromine is reduced as well as oxidised
Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms Which of the following oxides of carbon has fractional oxidation state?A. Carbon monoxideB. Carbon dioxideC. Carbon suboxideD. All of these
Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms Which of the following compounds have zero oxidation state at carbonA. `C_(6)H_(12)O_(6)`B. `HCOOH`C. HCHOD. `CH_(4)`
The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))` Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of carbon is zero?A. `CH_(4)`B. `CH_(3)OH`C. `CH_(2)O`D. HCOOH
In which of the following pairs. the oxidation states, of sulphuric and chromium are same?A. `SO_(3)^(2-),CrO_(4)^(2-)`B. `SO_(3),CrO_(4)^(2-)`C. `SO_(2),CrO_(4)^(2-)`D. `SO_(2),Cr_(2)O_(7)^(2-)`
Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as `"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)` Where, `n_(H), n_(O) and n_(C)` are number of respective atoms In which of the following compounds, the valency of carbon is two?A. CarbenesB. AllenesC. AlkenesD. Ketenes
The oxidation state of chromium in chromoium trioxide is:A. `+3`B. `+4`C. `+5`D. `+6`
In that compounds `KMnO_(4) and K_(2)Cr_(2)O_(7)` the highest oxidation state the element:A. potassiumB. chromiumC. oxygenD. maganse
Nitrogen forms a variety of compounds in all oxidation states ranging from:A. `-3 "to"+5`B. `-3 "to"+3`C. `-3 "to"+4`D. `-3 "to"+6`
When `SO_(2)` is passed through acidic solution of potassium dichromate, then chromium sulphate is formed. Change in valency of chronium isA. `+4 "to" +2`B. `+6"to"+3`C. `+7"to"+2`D. `+5"to"+3`

The missing tenn in the following equation is: `2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+...`A. `Sn^(4+)`B. `Sn^(3+)`C. `Sn^(2+)`D. `Sn^(+)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment