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The mixture containing the same number of molecules as that of 14 g of CO is |
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Answer» 14g of nitrogen + 16G of oxygen `14g=(14)/(28)=(1)/(2)` moles `7gmN_(2)+8gmO_(2)` `(7)/(28)+(8)/(32)=(1)/(4)+(1)/(4)=(1)/(2)` |
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