1.

The mixture containing the same number of molecules as that of 14 g of CO is

Answer»

14g of nitrogen + 16G of oxygen
7g of nitrogen + 16g of oxygen
14g of nitrogen + 8g of oxygen
7g of nitroen + 8g of oxygen

Solution :same molecules implies same MOLES
`14g=(14)/(28)=(1)/(2)` moles
`7gmN_(2)+8gmO_(2)`
`(7)/(28)+(8)/(32)=(1)/(4)+(1)/(4)=(1)/(2)`


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