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The Mn^(3+) ion is unstable in solutin and undergores disproportionation to give Mn^(2+),MnO_(2) and H^(+) ion write a balanced ionic equation for the reaction |
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Answer» Solution :The skeletal equation is `Mn^(3+)+(aq)rarrMn^(2+)(aq)+MnO_(2)(s)+H^(+)(aq)` Oxidation half equation `overset(+3)Mn^(3+)(aq)rarr overset(3+)(aq)rarr MnO_(2)(s)+4H^(+)(aq)+E^(-)` balance O atoms by adding `2H_(2)O : overset(2+)Mn^(3+)rarr Mn^(2+)` balance O.N by adding ELECTRONS `Mn^(3+)(aq)^(-)rarrMn^(2+)(aq)` adding Eq (i) and Eq (ii) the balanced equation for the disportionation reaction is `2Mn^(3+)(aq)+2H_(2)O(l)rarrMnO_(2)(s)+4H^(+)(aq)+e^(-)` balance O atoms by adding `2H_(2)Mn(aq)+2H_(2)O(l)rarrMnO_(2)(s)+4H^(+)(aq)+e^(-)` reduction half equation `overset(+3)Mn^(3+)rarr overset(Mn^(2+)` ltbalance O.N by adding electron `Mn^(3+) (aq)+e^(-)rarrMn^(2+)(aq)` adding eq (i) and eq (ii) the balanced equation for disproportion reaction is `2 Mn^(3+)(aq)+2H_(2)O+2H_(2)O(l)rarrMnO_(2)(s)+Mn^(2+)(aq)+4H^(+)(aq)` |
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