1.

The molal depreesion constant of water is 1.86^(@)C//m. Then find out the freezing point of 0.1 m NaCl solution.

Answer»

`-1.86^(@)C`
`0.372^(@)C`
`-0.372^(@)C`
`-0.186^(@)C`

SOLUTION :For NACL, i = 2
`Delta T_(f)=2K_(f).m`
`= 2xx1.86xx0.1=0.372`
`T_(s)=T-Delta T_(f)=0-0.372=-0.372^(@)C`.


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