1.

The molal elevation constant for water is 0.52 K. "molality"^(-). The elevation caused in the boiling point of water by dissolving 0.25 mole of a non volatile solute in 250 g of water will be :

Answer»

`52^(@)`
`5.2 ^(@)C`
`0.52^(@)C`
`0.052 ^(@)C`

Solution :`(Delta T_(f)=1000 XX K_(f))/W_(1) xx W_(2)/M_(2)=(1000 xx K_(f))/W_(1)xx n`
`Delta T_(f) = (1000 xx 0.52)/250 xx 0.25 =0.52^(@)C`


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