InterviewSolution
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InterviewSolution
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The molal elevation constant for water is 0.52 K. `"molality"^(-)`. The elevation caused in the boiling point of water by dissolving 0.25 mole of a non volatile solute in 250 g of water will be :A. `52^(@)`B. `5.2 ^(@)C`C. `0.52^(@)C`D. `0.052 ^(@)C` |
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Answer» Correct Answer - C `(Delta T_(f)=1000 xx K_(f))/W_(1) xx W_(2)/M_(2)=(1000 xx K_(f))/W_(1)xx n` `Delta T_(f) = (1000 xx 0.52)/250 xx 0.25 =0.52^(@)C` |
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