1.

The molal elevation constant of water = 0.52^(@)C kg mol^(-1). The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), therefore, should be

Answer»

`100.52^(@)C`
`101.04^(@)C`
`99.48^(@)C`
`98.96^(@)C`

Solution :`Delta T_(B) =imk_(b)=0.52xx1xx2=1.04`.
`THEREFORE T_(b)=100+1.04=101.04^(@)C`.


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