1.

The molal freezing point constant of water is 1.86^(@)C//M. Therefore the freezing point of 0.1 M NaCl solution in water is expected to be

Answer»

`-1.86^(@)C`
`-0.186^(@)C`
`-0.372^(@)C`
`+0.372^(@)C`

SOLUTION :`NaCl rarr Na^(+)+CL^(-)`, I = 2
`DeltaT_(f)=iK_(f)m=2xx1.86xx0.1=0.372^(@)C`,
`T_(f)=-0.372^(@)C`.


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