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The molal freezing point depression constant of benzene (C_(6)H_(6)) is "4.90 K kg mol"^(-1). Selenium exists as a polymer of the type Se_(x). When 3.26 g of selenium is dissolved in226 g of benzene the obsereved freezing point is 0.112^(@)C lower than for pure benzene. Deduce the molecular formula of selenium ("At. mass of Se =78.8 g mol"^(-1)). |
| Answer» SOLUTION :`Se_(8)` | |