1.

The molality of 3M solution os mehtanol if thedensity of the solution is 0.9g cm^(-3), is

Answer»

3.73
`3.0`
3.33
3.1

SOLUTION :`"Volume of the solution="1 L or 1000 cm^(3)`
`"Mass of the solution "=vxxd `
`= (1000CM(3)) xx (0.9 g cm^(3))=900 g`
`"Mass of methanol"(CH_(3)OH)=(3 molxx32 "g mol"^(-1))=96 g`
`"Mass of solvent" =(900-96g)=804 g=0.804 KG `
`"Molality of solution"=("No. of moles of methanol")/("Mass of solvent in kg")`
`(3mol)/(0.804kg)=0.373"mol kg"^(-1)`
=.373 MOLAL


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