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The molality of a solution of ethyl alcohol in water in 1.55 m. How many grams of ethyl alcohol are dissolved in 2kg of water ? |
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Answer» `("1.55 mol kg"^(-1))=(W)/(("46 g mol"^(-1))XX(2kg))` `W=("1.55 mol kg"^(-1))xx("46 g mol"^(-1))xx(2kg)=142.6g`. |
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