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The molality of the solution containing 45 g of glucose in 2 kg of water is …………. |
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Answer» Solution : `0.125m` `molality `= ("Number of moles of solute")/("MASS of the solvent in KG") = ((45)/(180))/(2) = (0.25)/(2) = 0.125m` (GLUCOSE = Molar mass = 180 g) |
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