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The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will beA. 101.5B. 139.5C. 203.5D. 279.5 |
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Answer» Correct Answer - B `lamda^(oo)BaCl_(2)=(1)/(2)lamda^(oo)Ba^(2+)+lamda^(oo)Cl^(-)` `=(127)/(2)+76=139.5ohm^(-1)cm^(-1)eq^(-1)`. |
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