1.

The molar conductances of NaCl,HCl and CH_(3)COONa at infinite dilution are 126.45, 426.16 and 91ohm^(-1)cm^(2)mol^(-1) respectively. The molar conductance ofCH_(3)COOH at infinite dilution is:-

Answer»

`201.28ohm^(-1)cm^(2)mol^(-1)`
`390.71ohm^(-1)cm^(2)mol^(-1)`
`698.28ohm^(-1)cm^(2)mol^(-1)`
`540.48ohm^(-1)cm^(2)mol^(-1)`

Solution :`(^^)_(m)^(@)(CH_(3)COOH)`
`=(^^)^(@)(CH_(3)COONA)+(^^)^(@)(HCL)-(^^)^(@)(NaCl)`
`=91+426.16-126.45=390.71ohm^(-1)cm^(2)mol^(-1)`


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