1.

The molar conductances of NaOH, NaCl and BaCl_(2) at infinite dilution are 2.481xx10^(-2), 1.265xx10^(-2) and 2.800xx10^(-2)" S "m^(2)mol^(-1) respectively. Calculate wedge_(m)^(@)Ba(OH)_(2).

Answer»


SOLUTION :`wedge_(m)^(@)[Ba(OH)_(2)]=wedge_(m)^(@)(BaCl_(2))+2wedge_(m)^(@)(BaCl_(2))+2wedge_(m)^(@)(NAOH)-2wedge_(m)^(@)(NACL)`.


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