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The molar conductivities of KCl, NaCl and `KNO_(3)` are 152,128 and `111" S cm"^(2) mol^(-1)` respectively. What is the molar conductivity of `NaNO_(3)` ?A. 101 S `cm^(2)mol^(-1)`B. 87 S `cm^(2)mol^(-1)`C. `-101`S `cm^(2)mol^(-1)`D. `-391`S `cm^(2)mol^(-1)` |
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Answer» Correct Answer - B `wedge_(K^(+))^(@)+wedge_(Cl^(-))^(@)=152S" "cm^(2)mol^(-1)` `wedge_(Na^(+))^(@)+wedge_(Cl^(-))=128S" "cm^(2)mol^(-1)` `wedge_(K^(+))^(@)+wedge_(NO_(3)^(-))^(@)=111S" "cm^(2)mol^(-1)` Now, `wedge_(NaNO_(3))=wedge_(NaCl)+wedge_(KNO_(3))-wedge_(KCl)` `wedge_(NaNO_(3))=87S" "cm^(2)mol^(-1)`. |
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