The molar conductivity of `0.05 M` of solution of an electrolyte is `200 Omega^(-1) cm^2`. The resistance offered by a conductivity cell with cell constant `(1//3) cm^(-1)` would be about .A. ` 11. 11 Omega`B. ` 22.22 Omega`C. ` 33.33 Omega`D. ` 44.444 Omega`

The molar conductivity of `0.05 M` of solution of an electrolyte is `2

1.	The molar conductivity of `0.05 M` of solution of an electrolyte is `200 Omega^(-1) cm^2`. The resistance offered by a conductivity cell with cell constant `(1//3) cm^(-1)` would be about .A. ` 11. 11 Omega`B. ` 22.22 Omega`C. ` 33.33 Omega`D. ` 44.444 Omega`
Answer» Correct Answer - C `k=Lambda_C = (200 s cm2 "mol"^(-1)) (.0.5 xx 10^(-3) "mol" cm^(-1))` ` = 0.01 S cm^(-1)` ` R=1/k (e/A) = 1/((0.01 S cm^(-1)) (1/3 cm^(-1)) = 33. 33 Omega`.

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The molar conductivity of `0.05 M` of solution of an electrolyte is `200 Omega^(-1) cm^2`. The resistance offered by a conductivity cell with cell constant `(1//3) cm^(-1)` would be about .A. ` 11. 11 Omega`B. ` 22.22 Omega`C. ` 33.33 Omega`D. ` 44.444 Omega`

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