1.

The molar conductivity of a 0.5 mol dm^(-3) solution of AgNO_3 with electrolytic conductivity of 5.76 xx 10^(-3)S cm^(-1) at 298 K is ………….. .

Answer»

`2.88 S cm^2 mol^(-1)`
`11.52 S cm^2 mol^(-1)`
`0.086 S cm^2 mol^(-1)`
`28.8 S cm^2 mol^(-1)`

SOLUTION :`LAMBDA = k/M xx 10^(-3) mol^(-1) m^(3)`
`= (5.76 xx 10^(-3) S cm^(-1) xx 10^(-3))/(0.5) mol^(-1) m^(3) = (5.76 xx 10^(-3) xx 10^(-3) xx 10^(6))/(0.5) S cm^(-1) mol^(-1) cm^3`
`= 11.52 cm^(2) mol^(-1)`.


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