The molar conductivity of acetic acid solution at infinite dilution is 390.7 `Omega^(-1)cm^(2)mol^(-1)`. Calculate the moalr conductivity of 0.01M acetic acid solution, given that the dissociation of acetic acid is `1.8xx10^(-5)`

The molar conductivity of acetic acid solution at infinite dilution is

1.	The molar conductivity of acetic acid solution at infinite dilution is 390.7 `Omega^(-1)cm^(2)mol^(-1)`. Calculate the moalr conductivity of 0.01M acetic acid solution, given that the dissociation of acetic acid is `1.8xx10^(-5)`
Answer» `underset(c(1-alpha))(CH_(3)COOH)hArrunderset(calpha)(CH_(3)COO^(-))+underset(calpha)(H^(+))` `K_(eq)=calpha^(2)" or "alpha=sqrt((K_(eq))/(c))=(wedge_(m)^(c))/(wedge_(m)^(oo))` `therefore(wedge_(m)^(c))/(390.7)=sqrt((1.8xx10^(-5))/(0.01))=sqrt(18xx10^(-4))=4.243xx10^(-2)` or `wedge_(m)^(c)=16.57Omega^(-1)cm^(2)`.

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The molar conductivity of acetic acid solution at infinite dilution is 390.7 `Omega^(-1)cm^(2)mol^(-1)`. Calculate the moalr conductivity of 0.01M acetic acid solution, given that the dissociation of acetic acid is `1.8xx10^(-5)`

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