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The molar conductivity of KCl solution at different concentrations at 298K are given below: {:(c//mol" "L^(-1),wedge//S" "cm^(2)mol^(-1),c//mol" "L^(-1),wedge//S" "cm^(2)mol^(-1)),(0.000198,148.61,0.000521,147.81),(0.000309,148.29,0.000989,147.09):} Show that the plot between wedge and c^(1//2) is a straight line. determine the values of wedge^(@) and A for KCl. |
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Answer» Solution :Taking the SQUARE root of concentration, we obtain `{:(c^(1//2)(mol" "L^(-1))^(1//2),wedge_(m)//S" "CM^(2)mol^(-1)),(0.01407,148.61),(0.01758,148.29),(0.02283,147.81),(0.03154,147.09):}` A plot of `wedge_(m)` (y-axis) and `c^(1//2)` (x-axis) is shown in the ADJOINING fig: It can be seen that it is nearly a straight LINE. from the intercept (i.e., when `c^(1//2)=0`), we find that `wedge_(m)^(@)=150.0" S "cm^(2)mol^(-1)` and `A=-"slope"=(Deltay)/(Deltax)=(150.0-147.0)/(0.034)` `=88.23" S "cm^(2)mol^(-1)//(mol//L^(-1))^(1//2)`. |
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