1.

The molar conductivity of solution of a weak acid HX (0.01 M)is ten times smaller than the molar conductivity of a solution of a weak. acid HY (0.1 M). If lambda_(x^(-))^(@) =lambda_(y^(-))^(@), the difference in their pK_(a) values, {pK_(a)(HX) - pK_(a)(HY)} is ..... . (Consider degree of dissociation of both acids to be lt lt 1.

Answer»


Solution :`(Lambda_(HX))/(Lambda_(HY)) = (1)/(10) = (alpha_(HX)//Lambda_(HX)^(@))/(alpha_(HY)//Lambda_(HY)^(@)) because alpha = (Lambda_(c))/(Lambda^(@))`
As`OVERSET(@)(lambda)_(X^(-)) = overset(@)(lambda)_(y^(-)), overset(@)(Lambda)_(HX) therefore (alpha_(HX))/(alpha_(HY)) = (1)/(10)`
`((K_(a))_(HX))/((K_(a))_(HY)) = (0.01 alpha_(HX)^(2))/(0.1 alpha_(HX)^(2))`


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