1.

The molar elevation constant for water is 0.52^(@). The elevation caused in the boiling point of water by dissolving 0.25 mole of a non-volatile solute in 250 g of water will be

Answer»

`0.52^(@)C`
`0.052^(@)C`
`5.2^(@)C`
`52^(@)C`

SOLUTION :MOLALITY of solution `=(0.25)/(250)xx1000=1`
`DeltaT_(B)=K_(f)xx m = 0.52xx1=0.52^(@)C`


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