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The molar heat capacity in a process of a diatomic gas if it does a work of `Q/4` when a heat of `Q` is supplied to it isA. `(2)/(5)R`B. `(5)/(2)R`C. `(10)/(3)R`D. `(6)/(7)R` |
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Answer» Correct Answer - c `dU=C_(v)dT=((5)/(2)R)dT` `rArr dT=(2(dU))/(5R)` From first law of thermodynamics, `dU=dQ=dW` or `dU=Q-(Q)/(4)=(3Q)/(4)` Now, molar heat capacity. `C=(dQ)/(dT)=(Q)/(2((dU)/(5R)))=(5QR)/(2((3Q)/(4)))=(10)/(3)R` |
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