1.

The molar heat capacity of Al is 24 J mol^(-1) K^(-1). The energy required to raise the temperature of 60.0g of Al from 25^(@)C to 45^(@)C is

Answer»

3.2 kJ
1.07 kJ
10.1 kJ
2.40 kJ

Solution :RISE in temperature = `45^(@) - 25^(@) = 20^(@)C`
Mass of Al = 60 g
Molar heat capacity of Al = `24 JK^(-1) mol^(-1)`
Specific heat capacity of Al,
`C = (24)/(27) = 0.889 JK^(-1) g^(-1)`
Energy required = `m XX c xx Delta T`
`= 60 xx 0.889 xx 20`
= 1066.8 or = 1.07 kJ


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