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The molar heat capacity of an ideal gas in a process varies as `C=C_(V)+alphaT^(2)` (where `C_(V)` is mola heat capacity at constant volume and `alpha` is a constant). Then the equation of the process isA. `Ve^(-((alphaT^(2))/(2R)))=` ConstantB. `Ve^(-((alphaT^(2))/(R)))=` constantC. `Ve^(-((2alphaT^(2))/(R)))=` constantD. `Ve^(-((3alphaT^(2))/(2R)))=` constant |
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Answer» Correct Answer - A Given `C=C_(V)+alphaT^(2)` `C_(V)+(RT)/(V)(dV)/(dT)=C_(V)+alphaT^(2)` `int(alphaT)/(R)dT=int(dV)/(V)+lnk` `(alphaT^(2))/(2R)=ln(kV)` `kV=e^((alphaT^(2))/(2R))` `thereforeVe^(-((alphaT^(2))/(2R)))`=constant |
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