The molar mass of a solute X in g mol^(-1), if its 1% solution is isotonic with a 5% solution of cane sugar (molar mass = 342 g mol^(-)), is

The molar mass of a solute X in g mol^(-1), if its 1% solution is isot

1.	The molar mass of a solute X in g mol^(-1), if its 1% solution is isotonic with a 5% solution of cane sugar (molar mass = 342 g mol^(-)), is
Answer» iron CONTENT in haemoglobin is 0.35% by mass 1 mole of haemoglobin contains 56 g iron 1 mole of haemoglobin contains 224 g iron if iron content is increased to 0.56%, molar mass of haemoglobin would be HIGHER than 65000 g `mol^(-1)` SOLUTION :`%Fe=(4xx56)/(65000)xx100=0.35%` weight Fe in 1 mole = `4xx56=224g` if % Fe `uarr`, m. WT `uarr`