1.

The molar mass of the solute sodium hydroxide obtained from the measurement of osmotic pressure of its aqueous solution at 27^(@)C is 25 g mol^(-1). Therefore, its ionization percentage in this solution is

Answer»

75
60
80
70

Solution :`i=(M_(C))/(M_(0))=(40)/(25)=1.6`
`{:(NaOHrarrNa^(+)+OH^(-)),("1 mol"),(1-alpha""alpha""alpha"Total "=1+alpha):}`
`i=1+alpha or alpha=i-1=0.6=60%`


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