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The molar ratio of Fe^(2+) to Fe^(3+) in a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) having equal number of sulphate ions in both ferrous and ferric sulphates is: |
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Answer» Solution :`FeSO_(4)rarrFe^(2+)+SO_(4)^(2-)` `Fe_(2)(SO_(4))_(3)rarr2Fe^(3+)+3SO_(4)^(2-)` Suppose X mole `SO_(4)^(2-)` ion are furnished by both `FeSO_(4)` and `Fe_(2)(SO_($))_(3)`. Number of moles of `Fe^(3+)=x` Number of moles of `Fe^(3+)=(2)/(3)x` `Fe^(2+):Fe^(3+)::x:(2)/(3)x` `=3:2` |
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