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The molar volume of 22 g of CO_(2) is….. |
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Answer» 44g of `CO_(2)` occupies molar volume=`2.24xx10^(-2)m^(3).` `:.` 2g of `CO_(2)` will occupy=`(2.24xx10^(-2))/cancel(44) XX cancel(22) =1.12xx10^(-2)L` |
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