1.

The molar volume of methane , CH_(4). At 819^(@)C and 760mm pressure is :

Answer»

<P>22.4L
44.8L
89.6L
5.6L

Solution :`V_(1) = 22.4L`
`p_(1) = 760 mm HG `
`T_(1) = 273K`
`V_(2) = ?`
`p _(2) `= 760mm Hg
`T_(2) = ` 1092 K
`( V_(2))/( T_(2)) = ( V_(1))/( T_(1))`
or `V_(2) = ( V_(1) T_(2))/( T_(1)) = ( 22.4 xx 1092)/( 273) = 89.6L`


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