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The molarconductivityat zeroconcentrationofNH_(4) CI NaOHand NaCIare respectively 149.7Omega^(-1) cm^(2) mol^(-1) 248.1 Omega^(-1) cm^(2) mol^(-1)and 126.5 Omega^(-1) cm^(2) mol^(-1). Whatis themolarconductivityof NH_(4)OH atzeroconcentration ? |
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Answer» `^^_(o_((NAOH)))=248.1 Omega^(-1) cm^(2) mol^(-1)` `^^_(o_((NaCI)))=126.5 Omega^(-1) cm^(2) mol^(-1)` By Kohlrausch's law `^^_(o_((NH_(4)OH)))= lambda_(NH_(4))^(0) + lambda_(OH^(-))^(0)""......(I)` `^^_(o_((NH_(4)C1)))=lambda_(NH_(4))^(0) + lambda_(C1)^(0)""......(i)` `^^_(o_((NaOH)))=lambda_(Na^(+))^(0) + lambda_(OH^(-))^(0) ""......(ii)` `^^_(0_((NaC1)))=lambda_(Na^(+))^(0) + LAMBDA _(C1^(-))^(0)""......(iii)` Addingequations(i) and (ii) and subtractingequation (iii) wegetequation I. `:. ^^_(o_((NH_(4)OH))) = ^^_(o_((NH_(4)C1))) + ^^_(0_((NaOH))) ^(-) ^^_(0_((NaC1)))` `=149.7 + 248 .1- 126. 5` `=271.3 Omega^(-1)cm^(2) mol^(-1)` |
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