1.

The molarity of 90% H_(2)SO_(4) solution is [density = 1.8 gm/ml]

Answer»

`1.8`
`48.4`
`91.83`
`94.6`

Solution :The density of solution = 1.8 gm/ml
Weight of one litre of solution = 1800 gm
`therefore` Weight of `H_(2)SO_(4)` in the solution `=(1800xx90)/(100)=1620 gm`
`therefore` Weight of solvent = 1800 - 1620 = 180 gm
`therefore` MOLALITY `=(1620)/(98)XX(1000)/(180)=91.83`


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