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The molarity of 90% `H_(2)SO_(4)` solution is [density = 1.8 gm/ml]A. `1.8`B. `48.4`C. `91.83`D. `94.6` |
Answer» Correct Answer - C The density of solution = 1.8 gm/ml Weight of one litre of solution = 1800 gm `therefore` Weight of `H_(2)SO_(4)` in the solution `=(1800xx90)/(100)=1620 gm` `therefore` Weight of solvent = 1800 - 1620 = 180 gm `therefore` Molality `=(1620)/(98)xx(1000)/(180)=91.83` |
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