1.

The molarity of 98% H_2SO_4(d = 1.8 g/mL) by weight is

Answer»

6 M
18 M
10 M
4 M

SOLUTION :98% `H_2SO_4` MEANS 98g `H_2SO_4` is in 100 g solution
volume of 100 g solution ` = (100)/(1.8) = 55.55 ml `
Molarity`= ("number of MOLES of " H_2SO_4)/("volume of solution ") xx 1000`
` = (98)/(98 xx 55.55) xx 1000 = 18 M `


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