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The molarity of a solution obtained by mixing 750 mL of 0.5(M) HCI with 250 mL of 2(M) HCI will be |
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Answer» 0.975(M) of HCl and 250mL of 2(M) HCl CONTAINS `2/(1000)xx250`=0.5 MOL of HCl. Volume of the resulting solution = 750 + 250 = 1000mL . Total NUMBER of moles of HCl in the solution = 0.375 + 0.5 = 0.875 mol `:.` Molarity of the resulting solution = 0.875(M) |
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