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The molarity of a solution obtained by mixing 800 ml of 0.5 M HCl with 200 ml of 1 M HCl will beA. 0.8 MB. 0.6 MC. 0.4 MD. 0.2 M |
Answer» Correct Answer - B `underset(("Initial"))(M_(1)V_(1))+M_(2)V_(2)=underset(("Final"))(M_(3)V_(3))` `V_(3)=V_(1)+V_(2)=800+200=1000` `M_(3)xx1000=0.5xx800+1xx200` `M_(3)=(600)/(1000)=0.6M`. |
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