1.

The molarity of HNO_(3) in a sample which has density 1.4 g/mL and mass percentage of 63% is …….

Answer»

14
12
8
6

Solution :Where, `%(w)/(w)=63%`
`rho = 1.4` g/mL
`M =((%(w)/(w)xx rho xx 10))/(MM)`
`M=((63xx1.4xx10))/(63)`
M = 14 mol/L


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