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The molarity of solution containing `15.20 g` of urea, (molar mass = 60) dissolved in `150 g` of water isA. `1.689 "mol" kg^(-1)`B. `0.1689` mol `kg^(-1)`C. `0.5922` mol `kg^(-1)`D. `0.2533` mol `kg^(-1)` |
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Answer» Correct Answer - A `W_(2) = 15.20g` `M_(2) = 60g mol^(-1)` `W_(1) = 150 g` m = ? Calculation : To Calculate molality `m=(W_(2))/(M_(2) xx W_(1)(kg))` `=(15.20 xx 10^(-3)kg)/(60 xx 10^(-3) kg mol^(-1) xx 150 xx 10^(-3) kg)` `=(15.20 xx 1000)/(60 xx 150) = (15.2 xx 10)/( 6 xx 15)` `m=(15.2 xx 10)/(90) = 15.2/9 = 1.689 mol kg^(-1)` |
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