1.

The mole fraction of a solute in a solution 0.1. At 298 K, molarity of this solution is the same as its molality. Density of this solution at 298 K is 2.0 g cm^(-3). The ratio of the molecular weight of the solute and solvent, ((MW_("solute"))/(MW_("solvent"))), is

Answer»


Solution :`m=(X_(A)xx1000)/(X_(B)xxM_(A))`
`m=(1000)/(9M_(A))`……(i)
`M=(n_(B)xx1000xxd)/(n_(A)xxM_(A)+n_(B)xxM_(B))=(X_(B)xx1000xx d)/(X_(A)xx M_(A)+X_(B)xxM_(B))`
`=(200)/(0.9M_(A)+0.1M_(B))=(2000)/(9M_(A)+M_(B))`……(ii)
As m = M
`(1000)/(9M_(A))=(2000)/(9M_(A)+M_(B))RARR 9M_(A)+M_(B)=18M_(A)`
`therefore 9M_(A)=M_(B) therefore (M_(B))/(M_(A))=9`


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