1.

The mole fraction of a solute in its solution in acetic acid is 0.2. The mass of solute (molar mass = 40) in 120g. Of acetic acid would be

Answer»

2 g
8 g
10 g
20 g

Solution :MOLE fraction of acetic acid = 1 - 0.2 = 0.8
:. Solution contains `0.8 xx 60 = 48 `g. of acetic acid and `0.2 xx 40 = 8 ` g of solute
:. 120 g acetic acid will contain` (8 xx 120)/48=20 g.` of solute.


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