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The mole fraction of a solute in its solution in acetic acid is 0.2. The mass of solute (molar mass = 40) in 120g. Of acetic acid would beA. 2 gB. 8 gC. 10 gD. 20 g |
Answer» Correct Answer - D Mole fraction of acetic acid = 1 - 0.2 = 0.8 :. Solution contains `0.8 xx 60 = 48 `g. of acetic acid and `0.2 xx 40 = 8 ` g of solute :. 120 g acetic acid will contain` (8 xx 120)/48=20 g.` of solute. |
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