1.

The mole fraction of methanol in its 4.5 molal aqueous solution is

Answer»

`0.250`
`0.125`
`0.100`
`0.075`

Solution :Let a mole of `CH_(3)OH` and b mole of WATER be PRESENT in the solution.
Mass of water `=b xx 18`
Molality of solution
`=(a)/(b xx 18)xx1000=4.5`
or `a/b=(18xx4.5)/(1000)=0.081`
Mole FRACTION of `CH_(3)OH`
`=(a)/(a+b)` or `(1)/(1+b//a)`
`=(1)/(1+(1)/(0.081))=(1)/(1+12.34)=0.075`


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