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The mole fraction of oxalic acid (Molar mass 63) required to prepare 0.10 m solution in water isA. 1B. 0.0018C. 6.3D. 0.0992 |
Answer» Correct Answer - B `X_(2)= (mM_(1))/(1000+mM_(1))` `=(0.1 xx 18)/(1000 + 0.1 xx 18)` =0.0018 |
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