1.

The mole fraction of solute in an aqueous solution is (1)/(112). The molality (m) of the solution is 0.1x. What is x?

Answer»


Solution :`(X_(1))/(X_(2))=(mM_(2))/(1000)IMPLIES(1//112)/(111//112)=(mxx18)/(1000)impliesm=0.5`


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