1.

The mole fraction of solute is 0.2 at that time the decrease in vapoure pressure is 10 mm. If the decrease in vapour pressure is 20 mm, then what will be the mole fraction of solute ?

Answer»

<P>`0.2`
`0.4`
`0.6`
`0.8`

Solution :`(p^(@)-p)/(p^(@))=(N)/(n+N)`
`(DELTA p)/(p^(@))=0.2` (given)
`(10)/(p^(@))=0.2 "" THEREFORE p^(@)=50`
Now `(p^(@)-p)/(p^(@))=(n)/(n+N)`
`therefore (20)/(50) = x "" x =0.4`


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