1.

The mole of fraction of nitrogen, in a mixture of 7 g of N_(2) and 16 g of O_(2) is

Answer»

0.5
0.75
0.66
0.33

Solution :MOLES of `N_(2) = 7/28=0.25` and
Moles of `O_(2) = 16/32 = 0.5`
MOLE FRACTION of `N_(2) = 0.25/(0.25 + 0.5)=0.33`


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