1.

The molecular mass of K_(2)Cr_(2)O_(7) is 294 amu. It acts as oxidising agent in a redox titration. Its equivalent mass in acid medium will be :

Answer»

294
49
147
74

Solution :`K_(2)overset(+12)(Cr_(2))O_(7)+4H_(2)SO_(4)to K_(2)SO_(4)+overset(+6)(Cr_(2)(SO_+(4))_(3)+4H_(2)O+3[O]`
Change in oxidation number = 6
EQUIVALENT mass `=("Molecular mass")/(6)=(294)/(6)=49`


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