1.

The molecular mass of NaCl determined by studying freezing point depression of it's 0.5% aqueous solution is 30. The apparent degree of dissociantion of NaCl is :

Answer»

0.95
`0.5`
`0.6`
`0.3`

SOLUTION :`i=1+ALPHA =("cal.m.wt.")/("exp.m.wt.")= 58.5/30`
`:. 1 + alpha = 1.95` `:. alpha =0.05`


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