1.

The molecule having smaller bond angle isA. `NC_(3)`B. `AsCI_(3)`C. `SbCI_(3)`D. `PCI_(3)`

Answer» Correct Answer - c
`{:(N),(P),(As),(Sb):}]{:("Group =15"),({:[("Valence"),("electros"):}]=5):}`
`MCI_(3)` has `sp^(2)` hybridized M- electron with one lone pair .Lone pair and bond repulsion decreases bond angle .However, the bond -pair of electron are much father away from the central atom than they are in `NCI_(1)` .Thus lone- pair cause ever greater distrotion in `PCI_(3)AsCI_(3) and SbCI_(2)` ,Tjus bond angle decreases from `NCI_(23)` (maximum ) to `SbCI+_(3)` (minimum)


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